WebMay 5, 2015 · Just replace your filter statement with: filter (as.integer (Epsilon)>2) More generally, if you have a vector of indices level you want to eliminate, you can try: #some random levels we don't want nonWantedLevels<-c (5,6,9,12,13) #just the filter part filter (!as.integer (Epsilon) %in% nonWantedLevels) Share Follow answered May 5, 2015 at … WebDec 19, 2016 · Two approaches are possible: your can use regular expressions to identify strings that could be converted to numbers, e.g., grepl ("^ [0-9]$", c ("1", "1.x", "x.1", "5.5"), perl = T) (see Regex for numbers only ).
dplyr - R: how to filter out rows that end with a specific list ...
WebApr 5, 2024 · I'm now trying to figure out a way to select data having specific values in a variable, or specific letters, especially using similar algorithm that starts_with() does. ... Is there a way to filter out rows if the first value in the rows meets a certain criteria. R. 298. Filter rows which contain a certain string. WebJan 7, 2024 · 3 Answers Sorted by: 1 You can construct exclude_list as : exclude_list = c ("GA", "CA") Then use subset as : subset (data, !grepl (sprintf (' (%s)$', paste0 (exclude_list, collapse = ' ')), Geography)) Or if you need dplyr answer do : library (dplyr) data %>% filter (!grepl (sprintf (' (%s)$', paste0 (exclude_list, collapse = ' ')), Geography)) breadth requirements cwru
R dplyr filter rows on numeric values for given column
WebMar 25, 2024 · If you are back to our example from above, you can select the variables of interest and filter them. We have three steps: Step 1: Import data: Import the gps data Step 2: Select data: Select GoingTo and DayOfWeek Step 3: Filter data: Return only Home and Wednesday We can use the hard way to do it: Web1 day ago · Part of R Language Collective Collective. 0. I have a dataframe in R as below: Fruits Apple Bananna Papaya Orange; Apple. I want to filter rows with string Apple as. Apple. I tried using dplyr package. df <- dplyr::filter (df, grepl ('Apple', Fruits)) But it filters rows with string Apple as: Apple Orange; Apple. Weba) To remove rows that contain NAs across all columns. df %>% filter(if_all(everything(), ~ !is.na(.x))) This line will keep only those rows where none of the columns have NAs. b) … cosmic wings rochester mn