WebJan 13, 2024 · If one follows the wave function realist in trying to explain nonlocality in terms of a common, higher-dimensional cause – the wave function – this leaves us with a way of resurrecting Schrödinger’s hope of providing a smooth and continuous realist interpretation of quantum mechanics. The higher dimensions are surprising. WebAug 13, 2024 · Continuing along the same lines, let us assume that a nonrelativistic electron in free space (no potentials, so no forces) is described by a plane wave: ψ(x, t) = Ae i ℏ ( px − Et) We need to construct a wave equation operator which, applied to this wave function, just gives us the ordinary nonrelativistic energy-momentum relationship, E = p2 / 2m.
Continuity & smoothness of wave function - Physics Stack …
WebMar 4, 2016 · 1 Continuity of the logarithmic derivative guarantees continuity of both the wave function and the derivative of the wave function, which is required in all cases of non-singular scattering potentials (delta-function potentials introduce discontinuities into the derivative of the wave function, but they're pretty unphysical). – march WebJan 1, 2015 · The statements about finiteness, continuity of first derivatives, etc., all have analogues in terms of finiteness of energy, force, or the ability to localize the wave. Also, those solutions may be valid on some finite domain that does not include singularities that are too severe. Share Cite Improve this answer Follow answered Jan 1, 2015 at 11:57 snabberwitch forumactif
Continuity of the wave function in quantum mechanics
WebDec 27, 2024 · It is not true the wave function has to be continuous, it just has to be measurable (i.e., a limit of step functions almost everywhere). Naturally you might wonder what sense Schroedinger's equation makes if you apply it to a step function...but the answer is easier than worrying about distributional weak solutions. WebIt is not true the wave function has to be continuous, it just has to be measurable (i.e., a limit of step functions almost everywhere). Naturally you might wonder what sense Schroedinger's equation makes if you apply it to a step function...but the answer is easier than worrying about distributional weak solutions. WebWhy the wave function, which is in the form of bessel function be zero at x=0 ,so also its derivative. In general wave function is zero at infinity ,as potential is infinity . I feel wave function ... snabbflirt.com